Submission #10045085

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Source Code Expand

#include <iostream>
#include <map>
#include <set>
#include <cmath>
#include <algorithm>
#include <vector>
#include <string>
#include <fstream>
#include <bitset>
#include <queue>
#include <stack>
#include <deque>
#include <complex>
#include <iomanip>
#include <stdio.h>
#include <string.h>
#include <random>
#include <functional>

using std::cin;
using std::cout;
using std::cerr;
using std::endl;

using std::map;
using std::set;
using std::bitset;
using std::vector;
using std::string;
using std::multimap;
using std::multiset;
using std::deque;
using std::queue;
using std::stack;
using std::pair;
using std::iterator;

using std::sort;
using std::stable_sort;
using std::reverse;
using std::max_element;
using std::min_element;
using std::unique;
using std::ios_base;
using std::swap;
using std::fill;

using std::setprecision;
using std::fixed;

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<long long> vl;
typedef string S;

ll min(ll a, ll b) {return a < b ? a : b;}
ll min(int a, ll b) {return a < b ? a : b;}
ll min(ll a, int b) {return a < b ? a : b;}
ll min(int a, int b) {return a < b ? a : b;}

ll max(ll a, ll b) {return a > b ? a : b;}
ll max(int a, ll b) {return a > b ? a : b;}
ll max(ll a, int b) {return a > b ? a : b;}
ll max(int a, int b) {return a > b ? a : b;}

namespace MySpace{

};

#define F(i, n) for (int (i) = 0; (i) != (n); (i)++)
#define fi first
#define se second
#define re return
#define all(x) (x).begin(), (x).end()

const int MOD = 1e9 + 7;

long long inq(long long a, long long b)
{
    if (b == 0) return 1;
    long long l = inq(a, b / 2);
    if (b % 2) return l * l % MOD * a % MOD;
    return l * l % MOD;
}

long long n, a;
long long dp[2200000];

signed main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    cin >> n >> a;
    for (int i = 2; i <= min(n, 2000000); i++) dp[i] = 1e9;
    for (int i = 1; i <= min(n, 2000000); i++)
    {
        for (int j = 1; j * i <= min(n, 2000000); j++)
        {
            dp[i * j] = min(dp[i * j], dp[i] + j + a);
        }
    }
    long long ans = n;
    for (long long i = 1; i * i / 4 <= n; i++)
    {
        ans = min(ans, dp[i] + (n + i - 1) / i);
    }
    cout << ans;
}

Submission Info

Judge Result