Submission #11608999

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Source Code Expand

#include <bits/stdc++.h>
using namespace std;
using ll = long long;

int main(){
    ll N;
    cin >> N;
    vector<ll> A(10000001, 1);
    vector<ll> B(0);
    for (ll i = 0; i < 10000000; i++)
    {   
        B.push_back(i + 1);
        if (A.at(i) == N) {
             break;
        }
        else if (A.at(i) > N){
            B.erase(B.begin() + A.at(i)-N -1 );
            break;
        }
        A.at(i + 1) = A.at(i) + (i + 2);
     
        
    }
    for (ll i: B)
    {
        cout << i << endl;
    }
    
    
}

Submission Info

Judge Result