CODE FESTIVAL 2016 Final

Submission #5401357

Source codeソースコード

#include <vector>
#include <iostream>
#include <cmath>
#include <map>
#include <unordered_map>
#include <algorithm>
#include <fstream>
#include <unistd.h>
#include <string>
#include <numeric>
#include <queue>
#include <deque>
#include <sstream>
#include <iomanip>
#include <set>
#include <stack>
#include <cassert>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<vl> vvl;
typedef vector<vvl> vvvl;
typedef vector<vi> vvi;
typedef vector<vvi> vvvi;
typedef vector<bool> vb;
typedef vector<vector<bool>> vvb;
typedef vector<vvb> vvvb;
typedef vector<vvvb> vvvvb;
typedef vector<string> vs;
typedef vector<vector<string>> vvs;
typedef vector<char> vc;
typedef vector<vector<char>> vvc;
typedef vector<double> vd;
typedef vector<vd> vvd;
typedef vector<vvd> vvvd;
typedef pair<int, int> P;
typedef pair<ll, ll> PL;
typedef vector<P> vp;
typedef vector<PL> vpl;
typedef vector<vector<P>> vvp;
typedef vector<vector<PL>> vvpl;
const int INF = 1001001001;
const ll LINF = 1e16;
const double pi = 3.1415926535897932;
const string endstr = "\n";
#define FOR(i, a, b) for(ll i = (a); i < b; i++)
#define REP(i, n) for(ll i = 0; i < n; i++)
#define FORMAP(it, m) for(auto it = m.begin(); it != m.end(); it++)
#define ff first
#define ss second
#define pb push_back

template <typename T>
T gcd(T a, T b) {
    return (a == 0) ? b : gcd(b%a, a);
}
template <typename T>
T lcm(T a, T b) {
    return a / gcd(a, b) * b;
}

bool p_comp_fs(const PL p1, const PL p2){ return p1.first < p2.first;};
bool p_comp_fg(const PL p1, const PL p2){ return p1.first > p2.first;};
bool p_comp_ss(const PL p1, const PL p2){ return p1.second < p2.second;};
bool p_comp_sg(const PL p1, const PL p2){ return p1.second > p2.second;};
template <typename T>
vector<T> uniquen(vector<T> vec){
    vec.erase(unique(vec.begin(), vec.end()), vec.end());
    return vec;
}


int main(){
    ll N; cin >> N;
    ll idx = 0;
    FOR(i, 0, N){
        ll summ = i*(i+1)/2;
        ll sump = (i+1)*(i+2)/2;
        if(summ < N && N <= sump){
            idx = i+1; break;
        }
    }
    ll rem = idx*(idx+1)/2 - N;
    FOR(i, 1, idx+1){
        if(i == rem) continue;
        cout << i << endstr;
    }
    return 0;
}

Submission

Task問題 B - Exactly N points
User nameユーザ名 k_k_hiroki
Created time投稿日時
Language言語 C++14 (GCC 5.4.1)
Status状態 AC
Score得点 300
Source lengthソースコード長 2327 Byte
File nameファイル名
Exec time実行時間 2 ms
Memory usageメモリ使用量 256 KB

Test case

Set

Set name Score得点 / Max score Cases
sample - sample-01.txt,sample-02.txt,sample-03.txt
dataset1 200 / 200 sample-01.txt,sample-02.txt,sample-03.txt,01-01.txt,01-02.txt,01-03.txt,01-04.txt,01-05.txt,01-06.txt,01-07.txt,01-08.txt,01-09.txt,01-10.txt
dataset2 100 / 100 sample-01.txt,sample-02.txt,sample-03.txt,01-01.txt,01-02.txt,01-03.txt,01-04.txt,01-05.txt,01-06.txt,01-07.txt,01-08.txt,01-09.txt,01-10.txt,02-01.txt,02-02.txt,02-03.txt,02-04.txt,02-05.txt,02-06.txt,02-07.txt,02-08.txt,sample-01.txt,sample-02.txt,sample-03.txt

Test case

Case name Status状態 Exec time実行時間 Memory usageメモリ使用量
01-01.txt AC 1 ms 256 KB
01-02.txt AC 1 ms 256 KB
01-03.txt AC 1 ms 256 KB
01-04.txt AC 1 ms 256 KB
01-05.txt AC 1 ms 256 KB
01-06.txt AC 1 ms 256 KB
01-07.txt AC 1 ms 256 KB
01-08.txt AC 1 ms 256 KB
01-09.txt AC 1 ms 256 KB
01-10.txt AC 1 ms 256 KB
02-01.txt AC 2 ms 256 KB
02-02.txt AC 2 ms 256 KB
02-03.txt AC 2 ms 256 KB
02-04.txt AC 2 ms 256 KB
02-05.txt AC 2 ms 256 KB
02-06.txt AC 1 ms 256 KB
02-07.txt AC 1 ms 256 KB
02-08.txt AC 2 ms 256 KB
sample-01.txt AC 1 ms 256 KB
sample-02.txt AC 1 ms 256 KB
sample-03.txt AC 1 ms 256 KB